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+ '''
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+ 풀이
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+ - 파이썬3 내장 함수인 bit_count() 함수 이용
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+
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+ 시간 복잡도: O(1)
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+
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+ 공간 복잡도: O(1)
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+ '''
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+
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+ class Solution :
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+ def hammingWeight (self , n : int ) -> int :
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+ return n .bit_count ()
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+
Original file line number Diff line number Diff line change
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+ '''
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+ 풀이
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+ - alphanumeric만 저장하는 alnum 배열 생성
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+ - alnum 배열의 절반 (소수점 버림) 길이를 순회하며 Palindrome 인지 확인
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+
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+ 시간 복잡도: O(n)
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+ - for loop * 2 -> O(2n) => O(n)
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+
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+ 공간 복잡도: O(n)
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+ - alphanumeric만 저장하는 alnum 배열이 최악의 경우 O(n) 일 수 있음
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+ '''
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+
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+ class Solution :
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+ def isPalindrome (self , s : str ) -> bool :
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+ alnum = []
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+ is_pal = True
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+ for c in s :
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+ if c .isalnum ():
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+ alnum .append (c .lower ())
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+
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+ for c in range (len (alnum ) // 2 ):
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+ if alnum [c ] != alnum [- 1 - c ]:
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+ is_pal = False
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+ break
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+
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+ return is_pal
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