Merge pull request #1530 from HoonDongKang/main

[HoonDongKang] Week 9 Solutions

Author: HoonDongKang

linked-list-cycle/HoonDongKang.ts

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+/**
+ * [Problem]: [141] Linked List Cycle
+ * (https://leetcode.com/problems/linked-list-cycle/description/)
+ */
+class ListNode {
+    val: number;
+    next: ListNode | null;
+    constructor(val?: number, next?: ListNode | null) {
+        this.val = val === undefined ? 0 : val;
+        this.next = next === undefined ? null : next;
+    }
+}
+
+function hasCycle(head: ListNode | null): boolean {
+    //시간복잡도 O(n)
+    //공간복잡도 O(n)
+    function setFunc(head: ListNode | null): boolean {
+        if (!head) return false;
+        const set = new Set<ListNode>();
+        let currentNode: ListNode = head;
+
+        while (currentNode) {
+            if (set.has(currentNode)) return true;
+
+            set.add(currentNode);
+            currentNode = currentNode.next!;
+        }
+
+        return false;
+    }
+    //시간복잡도 O(n)
+    //공간복잡도 O(1)
+    function pointerFunc(head: ListNode | null): boolean {
+        let slow = head;
+        let fast = head;
+        while (fast && fast.next) {
+            slow = slow.next;
+            fast = fast.next.next;
+
+            if (slow === fast) return true;
+        }
+        return false;
+    }
+}

maximum-product-subarray/HoonDongKang.ts

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+/**
+ * [Problem]: [152] Maximum Product Subarray
+ * (https://leetcode.com/problems/maximum-product-subarray/description/)
+ */
+function maxProduct(nums: number[]): number {
+    // 시간복잡도 O(n^2)
+    // 공간복잡도 O(1)
+    function bruteForce(nums: number[]): number {
+        let maxProduct = nums[0];
+
+        for (let i = 0; i < nums.length; i++) {
+            let product = 1;
+            for (let j = i; j < nums.length; j++) {
+                product *= nums[j];
+                maxProduct = Math.max(maxProduct, product);
+            }
+        }
+
+        return maxProduct;
+    }
+
+    // 시간복잡도 O(n)
+    // 공간복잡도 O(1)
+    function optimizedFunc(nums: number[]): number {
+        let maxResult = nums[0];
+        let minResult = nums[0];
+        let result = nums[0];
+
+        for (let i = 1; i < nums.length; i++) {
+            const num = nums[i];
+
+            if (num < 0) {
+                [maxResult, minResult] = [minResult, maxResult];
+            }
+
+            maxResult = Math.max(num, num * maxResult);
+            minResult = Math.min(num, num * minResult);
+            result = Math.max(result, maxResult);
+        }
+
+        return result;
+    }
+}

minimum-window-substring/HoonDongKang.ts

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+/**
+ * [Problem]: [76] Minimum Window Substring
+ * (https://leetcode.com/problems/minimum-window-substring/description/)
+ */
+function minWindow(s: string, t: string): string {
+    //시간복잡도 O(n)
+    //공간복잡도 O(n)
+    function windowFunc(s: string, t: string): string {
+        let left = 0;
+        let right = 0;
+        let s_map = new Map<string, number>();
+        let t_map = new Map<string, number>();
+        let minCount = Infinity;
+        let minStart = 0;
+
+        for (const char of t) {
+            t_map.set(char, (t_map.get(char) || 0) + 1);
+        }
+
+        while (right < s.length) {
+            let char = s[right];
+            s_map.set(char, (s_map.get(char) || 0) + 1);
+            right++;
+
+            while (isValid(s_map)) {
+                if (right - left < minCount) {
+                    minCount = right - left;
+                    minStart = left;
+                }
+
+                let char = s[left];
+                s_map.set(char, s_map.get(char)! - 1);
+                left++;
+            }
+        }
+
+        return minCount === Infinity ? "" : s.slice(minStart, minStart + minCount);
+
+        function isValid(map: Map<string, number>): boolean {
+            for (let i of t_map.keys()) {
+                if ((map.get(i) || 0) < t_map.get(i)!) return false;
+            }
+            return true;
+        }
+    }
+
+    //시간복잡도 O(n)
+    //공간복잡도 O(n)
+    function optimizedFunc(s: string, t: string): string {
+        const map = new Map<string, number>();
+        let required = t.length;
+        let left = 0;
+        let minLen = Infinity;
+        let minStart = 0;
+
+        for (const char of t) {
+            map.set(char, (map.get(char) || 0) + 1);
+        }
+
+        for (let right = 0; right < s.length; right++) {
+            const char = s[right];
+
+            if (map.has(char)) {
+                const count = map.get(char)!;
+                if (0 < count) required--;
+                map.set(char, count - 1);
+            }
+
+            while (required === 0) {
+                const char = s[left];
+
+                if (right - left + 1 < minLen) {
+                    minLen = right - left + 1;
+                    minStart = left;
+                }
+
+                if (map.has(char)) {
+                    map.set(char, map.get(char)! + 1);
+                    if (map.get(char)! > 0) {
+                        required++;
+                    }
+                }
+                left++;
+            }
+        }
+        return minLen === Infinity ? "" : s.slice(minStart, minStart + minLen);
+    }
+}

pacific-atlantic-water-flow/HoonDongKang.ts

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+/**
+ * [Problem]: [417] Pacific Atlantic Water Flow
+ * (https://leetcode.com/problems/pacific-atlantic-water-flow/description/)
+ */
+function pacificAtlantic(heights: number[][]): number[][] {
+    //시간복잡도 O(n)
+    //공간복잡도 O(n)
+    const result: number[][] = [];
+    const rows = heights.length;
+    const cols = heights[0].length;
+
+    const pacificArea: boolean[][] = Array.from({ length: rows }, () => Array(cols).fill(false));
+    const atlanticArea: boolean[][] = Array.from({ length: rows }, () => Array(cols).fill(false));
+
+    function dfs(visited: boolean[][], row: number, col: number) {
+        if (row < 0 || col < 0 || row >= rows || col >= cols) return;
+        if (visited[row][col]) return;
+
+        visited[row][col] = true;
+
+        [
+            [row - 1, col],
+            [row + 1, col],
+            [row, col - 1],
+            [row, col + 1],
+        ].forEach(([r, c]) => {
+            if (r >= 0 && c >= 0 && r < rows && c < cols) {
+                if (heights[r][c] >= heights[row][col]) {
+                    dfs(visited, r, c);
+                }
+            }
+        });
+    }
+
+    for (let i = 0; i < rows; i++) {
+        dfs(pacificArea, i, 0);
+        dfs(atlanticArea, i, cols - 1);
+    }
+    for (let j = 0; j < cols; j++) {
+        dfs(pacificArea, 0, j);
+        dfs(atlanticArea, rows - 1, j);
+    }
+
+    for (let i = 0; i < rows; i++) {
+        for (let j = 0; j < cols; j++) {
+            if (pacificArea[i][j] && atlanticArea[i][j]) {
+                result.push([i, j]);
+            }
+        }
+    }
+
+    return result;
+}

sum-of-two-integers/HoonDongKang.ts

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+/**
+ * [Problem]: [371] Sum of Two Integers
+ * (https://leetcode.com/problems/sum-of-two-integers/description/)
+ */
+function getSum(a: number, b: number): number {
+    // 시간복잡도 O(n)
+    // 공간복잡도 O(1)
+    while (b !== 0) {
+        const carry = a & b;
+        a = a ^ b;
+        b = carry << 1;
+    }
+    return a;
+}