diff --git a/SQL_exercise_01/1_questions_and_solutions.sql b/SQL_exercise_01/1_questions_and_solutions.sql
index d676e41..7e04f81 100644
--- a/SQL_exercise_01/1_questions_and_solutions.sql
+++ b/SQL_exercise_01/1_questions_and_solutions.sql
@@ -90,22 +90,17 @@ ORDER BY price ASC
   
 
 -- 1.16 Select the name of each manufacturer along with the name and price of its most expensive product.
-select max_price_mapping.name as manu_name, max_price_mapping.price, products_with_manu_name.name as product_name
-from 
-    (SELECT Manufacturers.Name, MAX(Price) price
-     FROM Products, Manufacturers
-     WHERE Manufacturer = Manufacturers.Code
-     GROUP BY Manufacturers.Name)
-     as max_price_mapping
-   left join
-     (select products.*, manufacturers.name manu_name
-      from products join manufacturers
-      on (products.manufacturer = manufacturers.code))
-      as products_with_manu_name
- on
-   (max_price_mapping.name = products_with_manu_name.manu_name
-    and
-    max_price_mapping.price = products_with_manu_name.price); 
+SELECT Products.Name as "Products Name",
+Products.Price as "Price",
+Manufacturers.Name as "Manufacture Company"
+from Products,Manufacturers
+where Products.Manufacturer = Manufacturers.Code
+and Products.Price =
+(
+select max(Products.Price)
+from Products
+where Products.Manufacturer = Manufacturers.Code
+);