syscall: relax TestUnshare

Fixes #17224.

Some systems have more than just "lo" in a fresh network namespace, due
to IPv6. Instead of testing for exactly 3 lines of output (implying 1
interface), just test to make sure that the unshare call resulted in
fewer interfaces than before. This should still verify that unshare did
something.

Change-Id: Iaf84c2b0e673fc207059d62e2f4dd7583a753419
Reviewed-on: https://go-review.googlesource.com/30372
Reviewed-by: Brad Fitzpatrick <[email protected]>
Reviewed-by: Jessica Frazelle <[email protected]>
Run-TryBot: Brad Fitzpatrick <[email protected]>
TryBot-Result: Gobot Gobot <[email protected]>

Author: quentinmit

src/syscall/exec_linux_test.go

@@ -162,6 +162,12 @@ func TestUnshare(t *testing.T) {
 		t.Fatal(err)
 	}
 
+	orig, err := ioutil.ReadFile(path)
+	if err != nil {
+		t.Fatal(err)
+	}
+	origLines := strings.Split(strings.TrimSpace(string(orig)), "\n")
+
 	cmd := exec.Command("cat", path)
 	cmd.SysProcAttr = &syscall.SysProcAttr{
 		Unshareflags: syscall.CLONE_NEWNET,
@@ -178,8 +184,8 @@ func TestUnshare(t *testing.T) {
 	}
 
 	lines := strings.Split(sout, "\n")
-	if len(lines) != 3 {
-		t.Fatalf("Expected 3 lines of output, got %d", len(lines))
+	if len(lines) >= len(origLines) {
+		t.Fatalf("Got %d lines of output, want <%d", len(lines), len(origLines))
 	}
 }