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rustc: Don't mark type parameters as exported
This ends up causing the privacy pass to get all confused, and there's nothing inherently exported about them anyway. Closes #14933
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src/librustc/middle/privacy.rs

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@@ -303,7 +303,7 @@ impl<'a> Visitor<()> for EmbargoVisitor<'a> {
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match ty.node {
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ast::TyPath(_, _, id) => {
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match self.tcx.def_map.borrow().get_copy(&id) {
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def::DefPrimTy(..) => {},
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def::DefPrimTy(..) | def::DefTyParam(..) => {},
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def => {
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let did = def.def_id();
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if is_local(did) {

src/test/run-pass/issue-14933.rs

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@@ -0,0 +1,15 @@
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// Copyright 2014 The Rust Project Developers. See the COPYRIGHT
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// file at the top-level directory of this distribution and at
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// http://rust-lang.org/COPYRIGHT.
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//
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// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or
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// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license
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// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your
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// option. This file may not be copied, modified, or distributed
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// except according to those terms.
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#![feature(default_type_params)]
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pub type BigRat<T = int> = T;
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fn main() {}

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