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25 changes: 25 additions & 0 deletions combination-sum/ohgyulim.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,25 @@
import java.util.*;

class Solution {
List<List<Integer>> answer = new ArrayList<>();
public List<List<Integer>> combinationSum(int[] candidates, int target) {
Arrays.sort(candidates);
recur(new ArrayList<Integer>(), candidates, target, 0, 0);
return answer;
}

public void recur(List<Integer> result, int[] candidates, int target, int sum, int index) {
if (sum == target) {
List<Integer> deepCopyRes = new ArrayList<>(result);
answer.add(deepCopyRes);
return;
}
for (int i = index; i < candidates.length; i++) {
if (sum + candidates[i] <= target) {
result.add(candidates[i]);
recur(result, candidates, target, sum + candidates[i], i);
result.remove(Integer.valueOf(candidates[i]));
}
}
}
}
Comment on lines +1 to +25
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백트래킹으로 깔끔하게 잘 푸신거 같습니다.

26 changes: 26 additions & 0 deletions decode-ways/ohgyulim.java
Original file line number Diff line number Diff line change
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class Solution {
/* 시간 복잡도: O(N)
* - for 루프: O(N)
* 공간 복잡도: O(N), dp배열
*/
public int numDecodings(String s) {
if (s.charAt(0) == '0') return 0;
int[] dp = new int[s.length() + 1];
dp[0] = 1;
dp[1] = 1;

for (int i = 2; i <= s.length(); i++) {
int one = Integer.parseInt(s.substring(i - 1, i));
int two = Integer.parseInt(s.substring(i - 2, i));

if (one > 0) {
dp[i] += dp[i - 1];
}
if (two >= 10 && two <= 26) {
dp[i] += dp[i - 2];
}
}
return dp[s.length()];
}
}

17 changes: 17 additions & 0 deletions maximum-subarray/ohgyulim.java
Original file line number Diff line number Diff line change
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class Solution {
/* 시간 복잡도: O(N)
* - for 루프: O(N)
* 공간 복잡도: O(N), dp배열
*/
public int maxSubArray(int[] nums) {
int[] dp = new int[nums.length];
dp[0] = nums[0];

int answer = nums[0];
for (int i = 1; i < nums.length; i++) {
dp[i] = Math.max(nums[i], dp[i - 1] + nums[i]);
answer = Math.max(answer, dp[i]);
}
return answer;
}
}
10 changes: 10 additions & 0 deletions number-of-1-bits/ohgyulim.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,10 @@
class Solution {
/* 시간 복잡도: O(1)
*
* 공간 복잡도: O(1)
*/
public int hammingWeight(int n) {
return Integer.bitCount(n);
}
Comment on lines +6 to +8
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자바는 이렇게 내장함수로 풀 수있는 방법이 되게 좋네요. 다만 꼭 내장함수 말고도 풀수있는 방법이 있다면 고민해보시는것도 좋을거 같아요.

}

26 changes: 26 additions & 0 deletions valid-palindrome/ohgyulim.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,26 @@
class Solution {
/* 시간 복잡도: O(N)
* - for 루프: O(N)
*
* 공간 복잡도: O(N), StringBuilder
*/
public boolean isPalindrome(String s) {
StringBuilder sb = new StringBuilder();

for (char ch : s.toCharArray()) {
if (Character.isLetterOrDigit(ch)) {
sb.append(Character.toLowerCase(ch));
}
}

for (int i = 0; i < sb.length(); i++) {
int left = i;
int right = sb.length() - i - 1;

if (left >= right) return true;
if (sb.charAt(left) != sb.charAt(right)) return false;
}

return true;
}
}