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[juliacall] how to broadcast a Julia function? #305

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Moelf opened this issue May 11, 2023 · 1 comment
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[juliacall] how to broadcast a Julia function? #305

Moelf opened this issue May 11, 2023 · 1 comment
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@Moelf
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Moelf commented May 11, 2023

similar to #285
@Moelf Moelf added the question Further information is requested label May 11, 2023
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cjdoris commented May 13, 2023

Broadcasting has a special syntax in Julia which doesn't naturally translate to Python. You have a couple of options, either create a function to do the broadcasting:

f = jl.seval("x -> sqrt.(x)")
f(x)

or use the broadcast function directly:

jl.broadcast(jl.sqrt, x)

@JuliaPy JuliaPy locked and limited conversation to collaborators May 13, 2023
@cjdoris cjdoris converted this issue into discussion #306 May 13, 2023

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