How to include source written in julia ?

[terasakisatoshi]

When we would like to use 3rd party library from Python via pyjulia
e.g. Images which is a Julia Package , we only have to use Main.using

from julia import Main
Main.using("Images")
img = Main.eval('load("path/to/img")') # where load is a function defined in Images package

On the other hand, is there any way import or incluide our own source code ?

For example I created a trivial example:

#example.jl
function echomsg(msg)
    return msg 
end

Then I would like to call echomsg defined above from Python.
I tried to from julia import Main; Main.eval('include("example.jl")') on python REPL
but failed with the following message

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/Users/terasakisatoshi/.pyenv/versions/miniconda3-3.19.0/lib/python3.5/site-packages/julia/core.py", line 739, in eval
    ans = self._call(src)
  File "/Users/terasakisatoshi/.pyenv/versions/miniconda3-3.19.0/lib/python3.5/site-packages/julia/core.py", line 672, in _call
    self.check_exception(src)
  File "/Users/terasakisatoshi/.pyenv/versions/miniconda3-3.19.0/lib/python3.5/site-packages/julia/core.py", line 722, in check_exception
    .format(exception, src))
julia.core.JuliaError: Exception 'UndefVarError: include not defined' occurred while calling julia code:
include("example.jl")

How should I do ???

[tkf]

#200 (comment) should fix the problem. Meanwhile, you can do:

from julia import Julia
julia = Julia()
julia.eval("@eval Main import Base.MainInclude: include")
from julia import Main
Main.include("...")

[terasakisatoshi]

@tkf

This work fine. Thank you !

#example.jl
function echomsg(msg)
    return join([msg, "Thank you !"], ". ")
end

def main():
    from julia import Julia
    julia = Julia()
    julia.eval("@eval Main import Base.MainInclude: include")
    from julia import Main

    Main.include("example.jl")
    msg = "This works file"
    print(Main.echomsg(msg))

if __name__ == '__main__':
    main()