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Add files via upload #4

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43 changes: 43 additions & 0 deletions js1/1.html
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<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>1</title>
</head>
<body>

<script type="text/javascript">

var digit1 = Number(prompt('Введите первое число')),
digit2 = Number(prompt('Введите второе число')),
digit3 = Number(prompt('Введите третье число'));
digit4 = Number(prompt('Введите четвертое число'));

if(digit1 > digit2 && digit1 > digit3 && digit1 > digit4) {
alert(digit1);
}
else if(digit2 > digit1 && digit2 > digit3 && digit1 > digit4) {
alert(digit2);
}
else if (digit3 > digit1 && digit3 > digit2 && digit3 > digit4) {
alert(digit3);
}
else if (digit4 > digit1 && digit4 > digit2 && digit4 > digit3) {
alert(digit4);
}

summ = Math.pow(digit1, -1) + Math.pow(digit2, -1) + Math.pow(digit3, -1) + Math.pow(digit4, -1);

summ2 = summ / 4;

summ3 = Math.pow(summ2, -1);

alert('среднее гармоническое этих четырёх чисел =' + summ3);



</script>

</body>
</html>
31 changes: 31 additions & 0 deletions js1/2.html
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<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>2</title>
</head>
<body>

<script type="text/javascript">

var digit1 = Number(prompt('Введите первое число')),
digit2 = Number(prompt('Введите второе число')),
digit3 = Number(prompt('Введите третье число'));

summ = digit1 + digit2;
summ2 = digit1 + digit3;
summ3 = digit2 + digit3;

if(digit1 < summ && digit1 < summ2 && digit1 < summ3 && digit2 < summ && digit2 < summ2 && digit2 < summ3 && digit3 < summ && digit3 < summ2 && digit3 < summ3) {
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Избыточное условие. Нужно проверить, чтобы сумма двух сторон была не меньше третьей, а не каждой из трех

alert("Вы ввели числа привильно");
}
else{
alert("вводите первые от наибольшего к наименьшему ; пример: 7, 4, 3тье число должно быть меньше 7+4 и меньше 7");
}


</script>

</body>
</html>
25 changes: 25 additions & 0 deletions js1/3.html
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<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>3</title>
</head>
<body>

<script type="text/javascript">

var digit1 = Number(prompt('Введите первое число')),
digit2 = Number(prompt('Введите второе число'));

if( digit1 % digit2 == 0) {
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Используйте строгое сравнение

alert("Остатка нет");
}
else{
alert("Остаток есть");
}

</script>

</body>
</html>
28 changes: 28 additions & 0 deletions js1/4.html
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<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>4</title>
</head>
<body>

<script type="text/javascript">

var digit1 = Number(prompt('Введите число 1099511627776'));

d1 = digit1 / 1024;

d2 = digit1 / 1048576;

d3 = digit1 / 1073741824;

alert(digit1 + "Байт");
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Нужно было вывести только одну единицу - самую подходяющую для значения

alert(d1 + "Килобайт");
alert(d2 + "Мегабайт");
alert(d3 + "Гигагабайт");

</script>

</body>
</html>
27 changes: 27 additions & 0 deletions js1/5.html
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<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>5</title>
</head>
<body>

<script type="text/javascript">

var a = Number(prompt('Введите число 1'));
var b = Number(prompt('Введите число 2'));
var c = Number(prompt('Введите число 3'));

p = 1/2 * (a + b + c);

s = p * (p - a) * (p - b) * (p - c);

s2 = Math.sqrt(s)

alert("Площать теугольника" + s2);

</script>

</body>
</html>
22 changes: 22 additions & 0 deletions js1/6.html
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<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>6</title>
</head>
<body>

<script type="text/javascript">

var year = Number(prompt('Введите год'));

if(year % 4 == 0 && year % 100 != 0 || year % 400 == 0){
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Используйте строгие сравнения и отрицания

alert("Год високосный");
}
else
alert("Год не високосный");
</script>

</body>
</html>