Description
What version of Go are you using (go version
)?
go version devel +1e3c57c Wed Nov 16 20:31:40 2016 +0000
with CL 33093 PS 4 cherry-picked on top, with GOEXPERIMENT=preemptibleloops
What operating system and processor architecture are you using (go env
)?
linux/amd64
What did you do?
I have a program that reads ~1MB records from stdin, decodes the records, and sends UDP datagrams. The program runs with around 20 goroutines. Around 40 copies of the program run on an 8-core host.
What did you expect to see?
I expected the 95th percentile of mark termination and sweep termination pauses to be 100µs or less.
What did you see instead?
The program's 95th percentile sweep termination time is around 60ms, and 95th percentile mark termination time is around 30ms. Here's an example gctrace line:
gc 11249 @74577.976s 0%: 11+185+35 ms clock, 90+143/358/582+280 ms cpu, 112->114->56 MB, 115 MB goal, 8 P
The mark termination pauses are very easy to identify in the execution trace—if this bug needs to be about either sweep term pauses or mark term pauses, let's use it for mark term.
Sweep termination pause distribution:
N 10000 sum 115454 mean 11.5454 gmean 0.602555 std dev 22.7221 variance 516.294
min 0.011
1%ile 0.014
5%ile 0.016
25%ile 0.023
median 0.34
75%ile 12
95%ile 59
99%ile 107
max 199
⠀⠀⠀⠀⠀⠀⠰⡄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⡖ 0.274
⠀⠀⠀⠀⠀⠀⡂⠄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⡇
⠠⠤⠤⠤⠤⠤⠄⠰⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠄⠧ 0.000
⠈⠉⠉⠉⠉⠉⠙⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠙⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠙⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠁
0 50 100
Mark termination pause distribution:
N 10000 sum 61391.3 mean 6.13913 gmean 0.93492 std dev 12.9254 variance 167.066
min 0.04
1%ile 0.053
5%ile 0.064
25%ile 0.1
median 0.82
75%ile 6.6
95%ile 29
99%ile 64
max 209
⠀⠀⠀⠀⠀⠀⠰⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⡖ 0.447
⠀⠀⠀⠀⠀⠀⡁⠄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⡇
⠠⠤⠤⠤⠤⠤⠄⠑⠒⠦⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠤⠄⠧ 0.000
⠈⠉⠉⠉⠉⠉⠙⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠋⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠉⠁
0 50
And here's the execution trace of a slow mark termination pause, taking over 16ms. Proc 6 organizes the mark termination phase. Procs 1, 2, 3, 4, and 5 execute it quickly at around t=1007ms. Proc 0 does mark termination around t=1014ms, and Proc 7 delays until t=1024ms at which point the global pause concludes.
Activity
rhysh commentedon Nov 17, 2016
/cc @aclements @RLH
dr2chase commentedon Nov 17, 2016
A quick sanity check -- does this mean that the total number of goroutines on your 8-core box is about 800? (40 copies times 20 goroutines). What's the OS scheduling quantum? How many of those per-process goroutines are eligible to run?
My first, lightly-informed guess is that some of the "running" goroutines are instead waiting to be given a core by the kernel, and they're not waiting at a Go safe point, so the thread cannot proceed to a safe point until the kernel says it can run, and the GC cannot finish a phase until all the threads have proceeded to a safe point.
rhysh commentedon Nov 17, 2016
Here's the execution trace of a 77ms mark termination pause:
Proc 0 does mark termination 72ms after Proc 4 begins the phase, and 68ms after the other straggler (Proc 1) observes the phase. There's an additional 5ms delay between when Proc 0 finishes its mark termination work and when Proc 4 declares the phase complete.
rhysh commentedon Nov 17, 2016
@dr2chase Yes, there would be around 800 goroutines total on the machine.
From
/proc/sys/kernel/sched_rr_timeslice_ms
, the scheduling quantum appears to be 25ms.Each instance of the program is generally idle, waiting for a record to come on stdin. When one arrives, it's processed by a single goroutine. That goroutine later hands the data off to another goroutine which does some more analysis. Each process usually has 0 running goroutines. Sometimes they'll have 1 running goroutine. Occasionally for bursts of around 100µs there'll be up to three goroutines running in parallel in a process.
The total CPU usage of all of the programs on that machine—including the 40 Go programs and the JVM process that feeds them data—is well below 8 cores when averaged over several seconds. If the threads are unable to execute, it's not from lack of CPU—at least in the average case. Are you asking if there might be sub-second bursts of high CPU demand?
I think the execution trace indicates that all goroutines/threads are at a safe point: there appears to be a "proc stop" event following each goroutine execution before the start of the mark termination phase. There may be a problem getting each P to be picked up by an M (with a core from the OS) in order to run the mark termination phase for that P .. but it doesn't look to me like there are goroutines pausing short of a safepoint.
I set
/proc/sys/kernel/sched_rr_timeslice_ms
to 1 on one machine, which doesn't seem to have had a significant impact on the GC pause durations:Sweep termination pause distribution:
Mark termination pause distribution:
RLH commentedon Nov 18, 2016
40 Go programs and a JVM competing for 8 HW threads managed by the OS could
result in one or more of the threads backing GOMAXPROCS being starved. The
fact that it is the thread is a GC thread isn't special. Go hasn't
attempted to solve these types of co-tenancy problems, they are hard. The
GC assumes that it is omnipotent and that GOMAXPROCS represents the number
of HW threads at its disposal.
The one thing that might help is that if you reduce GOMAXPROCS to 2 or 4 so
that when a GC does start it doesn't grab all 8 of the HW threads.
On Thu, Nov 17, 2016 at 6:29 PM, Rhys Hiltner notifications@github.com
wrote:
rhysh commentedon Nov 18, 2016
I've changed GOMAXPROCS to 2 and the tail latencies are now significantly better-controlled. Thanks @RLH!
The STW phases need to happen on each P .. why are GOMAXPROCS Ms required to do that? Without addressing co-tenancy in general, could the scheduler be adjusted so that once the bit of STW bookkeeping is done on a particular P, that the M would release that P and attempt to grab a P that still needs to complete the phase? A change like that might allow more programs to meet the GC pause goals without requiring tuning (of GOMAXPROCS).
Here are the distributions of the mark termination pauses with go version
devel +1e3c57c Wed Nov 16 20:31:40 2016 +0000
(meaning that the loop preemption patch is not active):GOMAXPROCS unset (defaulting to 8):
GOMAXPROCS manually set to 2:
RLH commentedon Nov 20, 2016
The problem isn't that the GC STW needs GOMAXPROCS HW threads to do its job. However, any critical path needs at least one and the other Go programs and the JVM are conspiring with the OS to prevent that. Any program's critical path could be delayed, it just happens that we are talking GC today. To make things worse if one of the conspirators is doing a concurrent mark it will recruit up to GOMAXPROCS idle Ps, potentially using up all the HW threads the OS is managing. The OS simple notes the pressure on the HW thread resource and takes away a HW thread in the middle of the STW's critical path and doesn't give it back for a long time.
The GOMAXPROCS=2 hack simply limits the HW threads the OS gives to any single Go program. Instead of 1 Go program being able to eat up all 8 HW threads it now takes 4. The numbers you reported seems to help confirm this.
rhysh commentedon Nov 25, 2016
So the change to GOMAXPROCS makes the processes less noisy for the benefit of their neighbors, rather than make the processes individually better-able to run in a noisy environment.
It sounds then like there's nothing to be done for a while, at least for Go 1.8. Should this issue be closed, or postponed/rolled into future co-tenancy work?
Thanks for helping me understand this behavior.
RLH commentedon Nov 25, 2016
[-]runtime: multi-ms mark termination pauses, even with loop preemption active[/-][+]runtime: aggressive GC completion is disruptive to co-tenants[/+]rhysh commentedon Nov 28, 2016
On the other hand, the Go runtime is becoming a noisier neighbor: the GC is getting better and better at completing quickly. Commit 0bae74e (for #14179) landed after I took this data, but looks like it will further those efforts. Since GOMAXPROCS defaults to NumCPU, even a mostly-idle daemon can create significant pressure on HW threads. This makes the host machine a noisier place for all programs.
Can Go be a less noisy neighbor by default? Is it worth addressing in Go 1.8 or 1.9?
To be specific: why is it beneficial to complete GC cycles quickly?
As the behavior and performance of the GC improves, what is the effect that the idle mark workers have on the performance of a single Go program? They seem to have a negative effect on neighboring programs, at least in aggregate.
/cc @RLH @aclements
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