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Fixes the join problem #218
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There is a problem here, as
$keyName
is also used below on line 103 in subquery and this needs to be in form of really just the key column name. If the table name is specified here, it won't work as the table is referenced by alias_
in the subquery.$keyName
should stay as is and the table name should be added only on line 117, where it is the only place where it is actually needed and preventsColumn '...' in where clause is ambiguous .
errors.That is also possibly the cause why the build if failing.
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Done