IDBKeyRange definition is degraded

[falsandtru]

IDBKeyRange is defined as follows.

https://github.com/Microsoft/TypeScript/blob/master/bin/lib.d.ts#L11630

interface IDBKeyRange {
    upper: any;
    upperOpen: boolean;
    lower: any;
    lowerOpen: boolean;
}
declare var IDBKeyRange: {
    prototype: IDBKeyRange;
    new(): IDBKeyRange;
    bound(lower: any, upper: any, lowerOpen?: boolean, upperOpen?: boolean): IDBKeyRange;
    only(value: any): IDBKeyRange;
    lowerBound(bound: any, open?: boolean): IDBKeyRange;
    upperBound(bound: any, open?: boolean): IDBKeyRange;
}

But it does not work.

new IDBKeyRange(); // error

Please recovery.

interface IDBKeyRange {
    upper: any;
    upperOpen: boolean;
    lower: any;
    lowerOpen: boolean;
    bound(lower: any, upper: any, lowerOpen?: boolean, upperOpen?: boolean): IDBKeyRange;
    only(value: any): IDBKeyRange;
    lowerBound(bound: any, open?: boolean): IDBKeyRange;
    upperBound(bound: any, open?: boolean): IDBKeyRange;
}

[DickvdBrink]

Except for the newable contructor the current one is right.
IDBKeyRange.only is like a static method and does not belong on the interface

[falsandtru]

How do I access to IDBKeyRange.only doing?

new IDBKeyRange().only // Runtime error
IDBKeyRange.only // Compile error

We can no longer access the IDBKeyRange method in the regular procedure.

[DickvdBrink]

IDBKeyRange.only("1"); works for me on the commandline (typescript 1.1.0.1 from NPM).
It doesn't work in Visual Studio using the 1.1 extension though, so there is something fishy there

[falsandtru]

When you have installed the VisualStudio, TypeScript that has been installed by npm is ignored.
In fact you may have used an older version of TypeScript.
Modification is required. Are you modify it?

[DickvdBrink]

@falsandtru, I installed the CTP for 1.1 for VS link

In short: npm 1.1 works
VS with 1.1 CTP doesn't work with intellisense and doesn't build.
VS with 1.0 you need to add the following to a file in your project ( I called mine extensions.d.ts and added the stuff from below)

declare var IDBKeyRange: {
    bound(lower: any, upper: any, lowerOpen?: boolean, upperOpen?: boolean): IDBKeyRange;
    only(value: any): IDBKeyRange;
    lowerBound(bound: any, open?: boolean): IDBKeyRange;
    upperBound(bound: any, open?: boolean): IDBKeyRange;
}

For clarification what are you using? Visual Studio version (if you use that) and TypeScript version?
I did not change lib.d.ts because that would cause issues with other guys in my team

[falsandtru]

I am fails to compile in tsc command from cmd.

Windows7 64bit
VS2013 WEB Express (not install CTP extension)
Nodejs 0.10.32
typescript 1.1.0-1 (npm)

[mhegazy]

@DickvdBrink something sounds strange, 1.1 CTP did not update the language service. so the language service is the same as you had in 1.0. so there should not be a change in behavior here. what are the errors are you seeing, and what is the definition of IDBKeyRange you have?

@falsandtru can you share the code that is failing to compile, along with the error you are getting?

This is building for me on 1.1, and latest from master.

IDBKeyRange.only("1");

[DickvdBrink]

@mhegazy, when using VS 14 CTP with 1.1 it works like a charm, IDBKeyrange has the interface and the declare var as shown by @falsandtru in his first post. This is a Machine running Windows 10 Preview and only has VS 14 on it.

Different machine Windows 8.1 with VS 2012 and 2013 and installed multiple versions on it coming from TypeScript 0.8.3 if I recall correctly is giving me the error Could not find symbol "IDBKeyRange".
VS 2013 (Ultimate) Update 3 with CTP 1.1 is loading the lib.d.ts from C:\MicroSd\Programs\Microsoft Visual Studio 12.0\Common7\IDE\CommonExtensions\Microsoft\TypeScript and only has the interface as shown below:

interface IDBKeyRange {
    upper: any;
    upperOpen: boolean;
    lower: any;
    lowerOpen: boolean;
    bound(lower: any, upper: any, lowerOpen?: boolean, upperOpen?: boolean): IDBKeyRange;
    only(value: any): IDBKeyRange;
    lowerBound(bound: any, open?: boolean): IDBKeyRange;
    upperBound(bound: any, open?: boolean): IDBKeyRange;
}

When I look in the microsoft sdks\typescript folder I have the 1.0 and the 1.1 folder both with a lib.d.ts.
The 1.0 has the same interface as in this post and the 1.1 as found in the Topic Start.

Note: I did install the CTP for VS 2013 (it is showing me the warning 'Your project file uses a newer version of the TypeScript compiler...blabla')

I never edited lib.d.ts manually or something and also tried to run a repair from the 1.1 CTP installer.
(Haven't tried to repair VS 2013 though)

Also: it is pretty funny because with the 1.0 release I added a extensions.d.ts file with the declare var IDBKeyRange stuff so I could use it with 1.0 and with 1.1 with that enabled it first whines about subsequent variable declarations must have the same type. and after disabling that it says `Could not find symbol``IDBKeyRange```

edited this post It didn't contain the error I was having .. xD

[falsandtru]

I will cancel the update. Please wait a little.

[mhegazy]

OK. now i see the problem..

you are redefining the var IDBKeyRange. The language does not allow changing the type of a var after it has been declared, this is diffrent from other constructs like an interface that can be augmented in later declarations. so something like:

var x: number;
var x: string;  /// error TS2403: Subsequent variable declarations must have the same type.  
                ///     Variable 'x' must be of type 'number', but here has type 'sting'.

what you want is for the definition of the var IDBKeyRange to define a new type that you can reopen later on, this is covered by #182.

the soultion here would be:

// lib.d.ts would define:
interface IDBKeyRange {
    upper: any;
    upperOpen: boolean;
    lower: any;
    lowerOpen: boolean;
}
interface IDBKeyRangeStatic {
    prototype: IDBKeyRange;
    new(): IDBKeyRange;
    bound(lower: any, upper: any, lowerOpen?: boolean, upperOpen?: boolean): IDBKeyRange;
    only(value: any): IDBKeyRange;
    lowerBound(bound: any, open?: boolean): IDBKeyRange;
    upperBound(bound: any, open?: boolean): IDBKeyRange;
}

declare var IDBKeyRange: IDBKeyRangeStatic;


// your file would update the static side
interface IDBKeyRangeStatic {
    myNewStaticHelperFunction();
}

Now for the next issue, defining the function on the interface is not probably what you mean. so if you look at the definition, there are two things:

1. interface IDBKeyRange, this defines the instance side of IDBKeyRange. i.e. objects of that type. i.e. things you get after calling new IDBKeyRange();
   this describes the runtime augmentation IDBKeyRange.prototype.blah = 3; that sets all instances of IDBKeyRange to have a property 'blah' with value 3;
2. var IDBKeyRange, this defines the static side of IDBKeyRange, i.e. the constructor object, i.e. the value you mean when you reference "IDBKeyRange". this describes the runtime augmentation IDBKeyRange.blah = 3; which adds a property blah, on the value IDBKeyRange.

var instance = new IDBKeyRange();
instance.upper;   // upper bounds of the value "instance", whose this object is "instance"

IDBKeyRange.upperBound // a static helper function that has no state associated with it.

adding upperBound on the interface, makes all instances of IDBKeyRange, have that, which is not what you want. what you want is a helper function on the static value side of IDBKeyRange.

hope that helps.

[DickvdBrink]

@mhegazy, should I creatie a new issue for the probleem i'm seeing with vs2013 because I think this one is a bit noisy (which is my fault, sorry bout that)

[mhegazy]

@DickvdBrink yes please. thanks for reporting this issue!

[falsandtru]

Wait, Duplication seems to be due to previous declaration that I do not show. It is not a Duplication of the definition file. Please anymore let a while verification.

[falsandtru]

The essential cause is I was found.
In the past examples of cancels all.

There are the following unnatural constraints. Is this would specification?

When IDBKeyRange I referring to the directly, I can use the method.
But it can not be referenced from a variable or class that was explicitly the type.
Perhaps this is I reproduce in other people.

Can not be defined only by inference the type of a variable.

IDBKeyRange.only('1'); // pass
var alias1 = IDBKeyRange;
alias1.only("1"); // pass
alias1.upperBound(1); // pass

var alias2: IDBKeyRange = IDBKeyRange; // error

error TS2322: Type '{ new (): IDBKeyRange; prototype: IDBKeyRange; bound(lower: any, upper: ny, lowerOpen?: boolean,...' is not assignable to type 'IDBKeyRange':  Property 'upper' is missing in type '{ new (): IDBKeyRange; prototype: IDBKeyRange; bound(lower: any, upper: any, lowerOpen?: boolean,...'.

Impossible to resolve the vendor prefix.

interface msIDBKeyRange extends IDBKeyRange {}
declare var msIDBKeyRange: IDBKeyRange;
var keyrange = IDBKeyRange || msIDBKeyRange;
keyrange.only('1'); // error

error TS2339: Property 'only' does not exist on type '{}'

Impossible to define the class interface.

class IDatabase {
  keyrange: IDBKeyRange
}

class Database implements IDBDatabase { // error
  keyrange = IDBKeyRange
}

var db: IDatabase = new Database();
db.keyrange.only(1);

error TS2421: Class 'Database' incorrectly implements interface 'IDBDatabase':  Property 'version' is missing in type 'Database'.

[mhegazy]

The issue here is a name can exist as a type and as a value. IDBKeyRange is both a var, and an interface. in type position (that is after the : in keyrange: IDBKeyRange, it is the type, but in keyrange = IDBKeyRange it is the value.

To create a new IDBKeyRange Object you must use one of the static helpers:

• IDBKeyRange .bound
• IDBKeyRange.only
• IDBKeyRange.lowerBound
• IDBKeyRange.upperBound

here is how you can get your samples to work.

class IDatabase {
    // keyrange is an instance of this type, a specific one.
    keyrange: IDBKeyRange
}

class Database implements IDatabase {
    // now create an instance of IDBKeyRange, either using bound, only, lowerBound, or upperBound.
    keyrange = IDBKeyRange.bound("A", "Z");
}

var db: IDatabase = new Database();
// this is the same instance you created when you created the object db
db.keyrange.upper; ///  === "Z"


// now let's create a new instance
var newKey = IDBKeyRange.only("1");
newKey.lower; /// === 1
newKey.upper; /// === 1

var myKey: IDBKeyRange = newKey; // OK
myKey.lower; /// === 1, still
myKey.upper; /// === 1, still