Unexpected "A 'super' call must be the first statement"

[eschwartz]

From #945

The first statement in the body of a constructor must be a super call if both of the following are true:
• The containing class is a derived class.
• The constructor declares parameter properties or the containing class declares instance member variables with initializers.

These don't seem to be the only two conditions.

Consider this:

class MyView extends Backbone.View {
   private someProp:SomeType;

  constructor(options:MyOptionsType) {
     // I want to create my view with these configured events:
     options.events = {
       'click .btn-close': this.close
     };
     super(options);

     this.someProp = new SomeType();
  }
}

This results in a compiler error: error TS2376: A 'super' call must be the first statement in the constructor when a class contains initialized properties or has parameter properties.

The MyView class does not contain initialized properties or parameter properties. What's going on here?

[eschwartz]

wait, nm. This was caused by my own mistake. sorry...

For anyone else having this issue, here's how I got confused

class MyView extends Backbone.View {
   private someProp:SomeType;

  constructor(options:MyOptionsType) {
     // I want to create my view with these configured events:
     options.events = {
       'click .btn-close': this.close
     };
     super(options);

     this.someProp = new SomeType();
  }

  // Converted incorrectly from JS 
  // MyView.prototype.mySuperCoolMethod = function() { }
  // Should be:
  // private mySuperCoolMethod() {}
  // Otherwise TypeScript considers this an "initialized property".
  private mySuperCoolMethod = function() {
  }
}