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!. after ?. should be warned #35071

@falsandtru

Description

@falsandtru

This is an anti-pattern on the current type system. And the compiler must not do quick fix so. !. after ?. is simply replaceable with ?. and should do so.

TypeScript Version: 3.7.x-dev.20191105

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Code

document.querySelector('_')!.textContent!.split('') // old code
document.querySelector('_')?.textContent!.split('') ?? 0 // string[]
document.querySelector('_')?.textContent?.split('') ?? 0 // string[] | 0

Expected behavior:

document.querySelector('_')!.textContent!.split('') // old code
document.querySelector('_')?.textContent!.split('') ?? 0 // unsafe, warning
document.querySelector('_')?.textContent?.split('') ?? 0 // safe

Actual behavior:

document.querySelector('_')!.textContent!.split('') // old code
document.querySelector('_')?.textContent!.split('') ?? 0 // unsafe, no warning
document.querySelector('_')?.textContent?.split('') ?? 0 // safe

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