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Hi,
I have a question. The following method worked in v1.0.21. However, it does not work in v1.0.24. The value of fileResponseOnYuz.result always returns null.
Is this a bug or am I doing something wrong?
Thanks.
File _image; ParseFile _imageParseFileOnYuz; _imageParseFileOnYuz = ParseFile(_image, name: nameOnYuz); ... var fileResponseOnYuz = await _imageParseFileOnYuz.save(); if (fileResponseOnYuz.success) { _imageParseFileOnYuz = fileResponseOnYuz.result as ParseFile; print("Image Save with success"); print(_imageParseFileOnYuz.file.uri); } else { print("Image Save with failed"); }
The text was updated successfully, but these errors were encountered:
Hi @alparslantopbas
the object _imageParseFileOnYuz is updated after save and contains information about ParseFile.
Is not necessary get return in results
Hi,
I have a question. The following method worked in v1.0.21. However, it does not work in v1.0.24. The value of fileResponseOnYuz.result always returns null.
Is this a bug or am I doing something wrong?
Thanks.
File _image;
ParseFile _imageParseFileOnYuz;
_imageParseFileOnYuz = ParseFile(_image, name: nameOnYuz);
...
var fileResponseOnYuz = await _imageParseFileOnYuz.save();
if (fileResponseOnYuz.success) {
_imageParseFileOnYuz = fileResponseOnYuz.result as ParseFile;
print("Image Save with success");
print(_imageParseFileOnYuz.file.uri);
} else {
print("Image Save with failed");
}
The text was updated successfully, but these errors were encountered: