Multiple assignment after declaration

[tstorch]

Currently multiple assignemnt is supported at declaration like this

let (critPos, period) =
    if critPos1 > critPos2 {
        (critPos1, period1)
    } else {
        (critPos2, period2)
    };

I think it would be nice to be able do something like this:

// "improved" version of  maximal_suffix in src/libcore/str.rs

fn maximal_suffix(arr: &[u8], reversed: bool) -> (uint, uint) {
    let mut left = -1; // Corresponds to i in the paper
    let mut right = 0; // Corresponds to j in the paper
    let mut offset = 1; // Corresponds to k in the paper
    let mut period = 1; // Corresponds to p in the paper

    while right + offset < arr.len() {
        let (a, b) =
            if reversed {
                (arr[left + offset], arr[right + offset])
            } else {
                (arr[right + offset], arr[left + offset])
            };
        // THIS IS THE IMPORTANT PART
        (left, right, offset, period) =
            if a < b {
                // Suffix is smaller, period is entire prefix so far.
                (left, right + offset, 1, right - left)
            } else if a == b {
                // Advance through repetition of the current period.
                if offset == period {
                    (left, right + offset, 1, period)
                } else {
                    (left, right, offset + 1, period)
                }
            } else {
                // Suffix is larger, start over from current location.
                (right, right + 1, 1, 1)
            };
    }
    (left + 1, period)
}

Currently something similar is at the moment only possible with a small workaround:

fn maximal_suffix(arr: &[u8], reversed: bool) -> (uint, uint) {
    let mut left = -1; // Corresponds to i in the paper
    let mut right = 0; // Corresponds to j in the paper
    let mut offset = 1; // Corresponds to k in the paper
    let mut period = 1; // Corresponds to p in the paper

    while right + offset < arr.len() {
        let (a, b) =
            if reversed {
                (arr[left + offset], arr[right + offset])
            } else {
                (arr[right + offset], arr[left + offset])
            };
        // HERE I NEED TO INTRODUCE TEMPORARY VARIABLES
        let (left_temp, right_temp, offset_temp, period_temp) =
            if a < b {
                // Suffix is smaller, period is entire prefix so far.
                (left, right + offset, 1, right - left)
            } else if a == b {
                // Advance through repetition of the current period.
                if offset == period {
                    (left, right + offset, 1, period)
                } else {
                    (left, right, offset + 1, period)
                }
            } else {
                // Suffix is larger, start over from current location.
                (right, right + 1, 1, 1)
            };
        // AND NOW I CAN PUT THE VALUES BACK IN THE REAL VARIABLES
        left = left_temp;
        right = right_temp;
        offset = offset_temp;
        period = period_temp;
    }
    (left + 1, period)
}

[rofrol]

dup of #10174

[steveklabnik]

Yes, closing as a duplicate.