Clarify how Rust treats backslashes at end of line in string literals #30727
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Rust differs in that behavior from C: In C, the newline escapes are resolved
before anything else, and in Rust this depends on whether the backslash is
escaped itself.
A difference can be observed in the following two programs:
```c
#include <stdio.h>
int main()
{
printf("\\
n\n");
return 0;
}
```
```rust
fn main() {
println!("\\
n");
}
```
The first program prints two newlines, the second one prints a backslash, a
newline, the latin character n and a final newline.
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@bors: r+ rollup thanks! |
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Jan 6, 2016
…eklabnik
Rust differs in that behavior from C: In C, the newline escapes are resolved
before anything else, and in Rust this depends on whether the backslash is
escaped itself.
A difference can be observed in the following two programs:
```c
int main()
{
printf("\\
n\n");
return 0;
}
```
```rust
fn main() {
println!("\\
n");
}
```
The first program prints two newlines, the second one prints a backslash, a
newline, the latin character n and a final newline.
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Rust differs in that behavior from C: In C, the newline escapes are resolved
before anything else, and in Rust this depends on whether the backslash is
escaped itself.
A difference can be observed in the following two programs:
The first program prints two newlines, the second one prints a backslash, a
newline, the latin character n and a final newline.